The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
width 1, length 10 width 2, length 5
Assuming the area is rectangular, the area is width * length = 2*1 = 1 square unit.
Length 1 and Width 17 Length 2 and Width 16 Length 3 and Width 15 Length 4 and Width 14 etc..... get the picture
Perimeter = 2 lengths + 2 widths 1/2 perimeter = length + width Length = 1/2 perimeter - width Area = length x width That's (1/2 perimeter - width) x (width) .
length 2 inches width 1 inch
It means one times the length and width
the width is 1 and the length is 2. 2 multipleyed by 1 equals 2...
The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
The length is 44 1/2 feet, and the width is 39 1/2 feet
width 1, length 10 width 2, length 5
Assuming the area is rectangular, the area is width * length = 2*1 = 1 square unit.
Bermuda is 21 miles in length and it's largest width is 1 mile.
Length 1 and Width 17 Length 2 and Width 16 Length 3 and Width 15 Length 4 and Width 14 etc..... get the picture
32.6 (rounded to 1 dp.) Method; Area = length x width Rearranging ... Length = Area / width Length = 228/7 = 32.6