53 and 47
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
It is: 6 squared + 8 squared = 100
The sum of the even numbers is (26 + 28 + ... + 100); The sum of the odd numbers is (25 + 27 + ... + 99) Their difference is: (26 + 28 + ... + 100) - (25 + 27 + ... + 99) = (26 - 25) + (28 - 27) + ... + (100 - 99) = 1 + 1 + ... + 1 There are (100 - 26) ÷ 2 + 1 = 38 terms above which are all 1; their sum is 38 x 1 = 38. So the difference of the sum of all even numbers and all odd numbers 25-100 is 38.
6
53 and 47
53 and 47
The numbers are 53 and 47
The two numbers are: 53 and 47 because 53+47 = 100 and 53-47 = 6
The numbers are 53 and 47
They are 47 and 53.
100/2 = 50 6/2 = 3 50 - 3 = 47 50 + 3 = 53 53 - 47 = 6 53 + 47 = 100
3 and 9 Difference: 9-3=6 Sum: 9+3=12
The difference, in a subtraction sum, is the answer to the sum. For example, the difference between 6 and 4 is equal to 2. 6 - 4 = 2.
Finding the sum is adding two numbers together. The product comes from multiplying them together. Therefore, the sum of 100 and 100 is 200. The product of 100 and 100 is 10,000. Thus, the difference (which comes from subtracting two numbers) between the two is 9,800.
8 and 6 have a difference of 2 and a sum of 14.
6 and 6