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What if your bank asks you to choose a 4 digit pin for your ATM card If the first number cannot be zero how many different possibilities are there for the pin?
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How many different telephone numbers can be formed from a seven digit number if the first and last digit cannot be zero?
The number of possibilities is 9 x 10 x 10 x 10 x 10 x 10 x 9 = 8,100,000.
How could you find the number of different combinations of 6 letters in a computer password?
there are 36 different combination possibilities. Try them all.
What number has a range of 5a median of 16 and a mean of 15?
A single number cannot have a range (other than 0), nor can it have a median that is different from its mean. A single number cannot have a range (other than 0), nor can it have a median that is different from its mean. A single number cannot have a range (other than 0), nor can it have a median that is different from its mean. A single number cannot have a range (other than 0), nor can it have a median that is different from its mean.
How many 3 digit numbers contain no repetition of digits?
Let's consider the following distribution: __ __ __ Each space represents one number. The first number can be anything from 0-9 (10 possibilities). The second number, after choosing the first number, can only have 9 possibilities. The reasoning behind this is if we choose the same number as the first, then there is a repetition. So we can't use that same number again. The third number can only have 8 possibilities by the same logic as for the second digit. Therefore there can be 10*9*8 = 720 3-digit numbers with no repetitions of digits.
How many 7 digit telephone numbers can be formed if the first three digits cannot be 800 and the first digit cannot be 0?
There are nine possibilities for the first digit. If this digit is not 8, there are ten possibilities for each of the remaining digits. Thus, if the first digit is not 8, there are 8 X 106 possibilities. If the first digit is 8, there are only nine choices for the second and third digits, since zero is excluded. This gives 9 X 9 X 104 possibilities that begin with 8. The total number of possibilities is therefore the sum of these two possibilities, which is 9.81 X 106 = 9,810,000.
What is a disambiguation?
Where something might have a number of meanings, the various possibilities are set out so people can choose which one they really mean.
How many ways can the director choose a quartet that contains at least one sopano if the chorus has six sopranos and eight baritones.?
There are 15 possibilities. In psuedo-code, the math works out like this: n = 42-1 where n is the number of possibilities, 4 is the size of a quartette, 2 is the number of different types of singers, and -1 reflects that a quartet of all non-sopranos does not meet your criteria.
How many different telephone numbers can be formed from a seven digit number if the first and last digit cannot be zero?
The number of possibilities is 9 x 10 x 10 x 10 x 10 x 10 x 9 = 8,100,000.
How could you find the number of different combinations of 6 letters in a computer password?
there are 36 different combination possibilities. Try them all.
What number has a range of 5a median of 16 and a mean of 15?
A single number cannot have a range (other than 0), nor can it have a median that is different from its mean. A single number cannot have a range (other than 0), nor can it have a median that is different from its mean. A single number cannot have a range (other than 0), nor can it have a median that is different from its mean. A single number cannot have a range (other than 0), nor can it have a median that is different from its mean.
How many different ways can you arrange 7 letter words?
The best way to think of this is how many options there are for each letter. There are 7 possibilities for the first letter. Then there are 6 possibilities (out of the remaining letters) for the second latter. Then 5 possibilities for the next, and so on. The total number of possibilities will be 7x6x5x4x3x2x1, which equals 5,040. So there are 5,040 different ways to arrange 7 letter words.
How many strings of four decimal digit have exactly three digit that are nine?
The number of strings of four decimal digits that have exactly three digits which are nine is the number of ways to choose three places to choose the nines multiplied by the number of possibilities for the other digits (because you can put all of the possibilities in an array so that each column has a different way of arranging the nines and that each row has a different set of other digits (because they do not affect each other)). The number of ways to choose the three places to choose the nines is the same as the number of ways of choosing 4-3=1 spot for there not to be a nine. The number of ways of choosing 1 spot where there are 4 spots is 4 (the first, the second, the third, or the fourth). Since there are 9 digits that are not nine, the number of choices for the other digits is 9 (since there is only one digit). Thus, there are 4*9=36 strings of four decimal digits that have exactly three digits which are nine.
How do you choose an area code for your Sprint phone?
Normally, you choose the area code that you live in, but you can choose a different area code if you want your phone number to be associated with a different specific city.
How many total possibilities are there if you know the first number but not the second two but you know that all three numbers are different?
360
How many 3 digit numbers contain no repetition of digits?
Let's consider the following distribution: __ __ __ Each space represents one number. The first number can be anything from 0-9 (10 possibilities). The second number, after choosing the first number, can only have 9 possibilities. The reasoning behind this is if we choose the same number as the first, then there is a repetition. So we can't use that same number again. The third number can only have 8 possibilities by the same logic as for the second digit. Therefore there can be 10*9*8 = 720 3-digit numbers with no repetitions of digits.
How many 7 digit telephone numbers can be formed if the first three digits cannot be 800 and the first digit cannot be 0?
There are nine possibilities for the first digit. If this digit is not 8, there are ten possibilities for each of the remaining digits. Thus, if the first digit is not 8, there are 8 X 106 possibilities. If the first digit is 8, there are only nine choices for the second and third digits, since zero is excluded. This gives 9 X 9 X 104 possibilities that begin with 8. The total number of possibilities is therefore the sum of these two possibilities, which is 9.81 X 106 = 9,810,000.
If the atomic number of 4 different elements is 102 what does itmean?
Atomic number is unique. It cannot be same for different elements.
