x + 3x + 3 = 4x + 3
No, -3 + 8 = 5.
The first integer is 17.
If the sum of each digit of a number is divisible by three ((1 + 1 + 1 + 0)/3 = 1) and it gives an integer, and the number is divisible by 2 (1110/2 = 555) and also gives an integer, then the number is divisible by 6.So, yes.
The sum is the answer when you have added. ex. 2+3, the sum is 5.
x + 3x + 3 = 4x + 3
-3
No, -3 + 8 = 5.
8
It's not always. 7 + (-3) = 4
6 6+(3*62) = 114
The sum is 3*(x-1) or 3x - 3
The first integer is 17.
By the uniqueness of integers, the only integer for 39 is 39 itself. And that cannot have a sum of 3.
If the sum of each digit of a number is divisible by three ((1 + 1 + 1 + 0)/3 = 1) and it gives an integer, and the number is divisible by 2 (1110/2 = 555) and also gives an integer, then the number is divisible by 6.So, yes.
sqrt 9 = +3 or 3 3 - 7 = -4 -3-7 = -10 the sum is an integer
The sum is the answer when you have added. ex. 2+3, the sum is 5.