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The sum is 3*(x-1) or 3x - 3

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Three times the sum of three consecutive integers is 72 what are the integers?

72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.


The sum of three consecutive integers is 13 greater than twice the smallest of the three integersfind the integer?

Integers are n, n + 1 and n + 2, so 3n + 3 = 13 + 2n Subtract 2n from each side: n + 3 = 13 Subtract 3 from each side: n = 10 Job done.


What is the sum of three consecutive integers of 180?

1+8+0 = 9 or 180+80+0 = 260


What is the sum of three consecutive integers is -123?

Algebraically. X = integer. X + (X + 1) + (X + 2) = - 123 3X + 3 = - 123 3X = - 126 X = - 42 X + 1 = - 41 X + 2 = - 40 - 42 + - 42 + - 40 = -123 =======


What are three consecutive integers that equal 171?

I'm assuming this is supposed to say: "What are three consecutive integers that add together to equal 171?"This could also be "What are three consecutive integers that multiply together to equal 171?"I will do both.For the addition caseThink of "three consecutive integers" as the expressions x, x+1, and x+2. For any value of x, these three expressions will give that number, the number that is one greater than it, and the number that is two greater than it. So, the expression x+(x+1)+(x+2) is the general sum of three consecutive integers. Also possible is the expression x+(x-1)+(x-2), which are still three consecutive integers. So, this is a simple equation:x+(x+1)+(x+2)=171x+x+1+x+2=1713x+3=1713x=168x=168/3x=56Since x=56, x+1=57 and x+2=58So the three numbers are 56,57,and 58You can check this answer by adding the three numbers together. I'll bet they equal 171.For the multiplication case:Refer to the explanation for the addition case, but instead of the end expression being x+(x+1)+(x+2), it is now the multiplication of the three integers, meaning the expression is (x)(x+1)(x+2), so we get: (x)(x+1)(x+2)=171(x)(x2+3x+2)=171x3+3x2+2x=171I'll admit right now I don't know a simple way to solve this equation, which hints to me that addition was the intent of the question, but this equation can be solved by plotting the equationsy=x3+3x2+2xy=171and finding their point(s) of intersection. The value comes out to be approximately 4.6106, which means that the numbers 4.6106, 5.6106, and 6.6106 will multiply to equal approximately 171 (but not exactly). No exact answer is really possible here.

Related Questions

The sum of the three consecutive integers?

The sum of three consecutive integers is -72


Three consecutive integers have a sum of 12. What is the greatest of these integers?

Three consecutive integers have a sum of 12. What is the greatest of these integers?


What is the second integer if three consecutive integers have the sum of 153?

51


What three consecutive negative integers have a sum of -56?

This would be impossible - since the mean of the three integers would have to be an integer, and if you divide -56 by 3, you do not get an integer.


Write the sum of three consecutive integers using l where l the middle integer of the three?

The sum of three consecutive integers can be expressed using ( l ) as the middle integer. The three integers can be represented as ( (l-1) ), ( l ), and ( (l+1) ). Therefore, the sum is ( (l-1) + l + (l+1) = 3l ).


What is the greatest of three consecutive integers whose sum is 30?

11


What is the sum of three consecutive odd integer is negative 31?

There is no set of three consecutive odd or even integers whose sum is negative 31.


Three-fourths of the sum of two consecutive integers?

0.75*(2n+1) where n is an integer.


What are three consecutive integer of 66?

21, 22 and 23.


What is the sum of the three consecutive odd integer of 165?

The integers are 53, 55 and 57.


What is the sum of three consecutive integers if n is the first integer?

The sum of three consecutive integers starting with ( n ) can be expressed as ( n + (n + 1) + (n + 2) ). Simplifying this expression gives ( 3n + 3 ). Therefore, the sum of the three consecutive integers is ( 3n + 3 ) or ( 3(n + 1) ).


How Find three consecutive even integers such that three times the first integer i six more than twice the second integer?

They are 14, 16 and 18.