The integers between -6 and 12 are: -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, and 11.
(-8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9)
+6 and -3 or -6 and +3. And by the way, these are not "intergers". They're "integers".
Excluding the numbers in the question, the integers which fall between 2 and 8 are 3, 4, 5, 6, and 7.
Assuming that there is an equality sign between the two sevens, the equation is an example of the Abelian (or commutative) property of integers (or numbers) under addition.
The integers between -6 and 12 are: -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, and 11.
-4
5
(-8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9)
Three: 1, 2, and 3.
+6 and -3 or -6 and +3. And by the way, these are not "intergers". They're "integers".
3
Excluding the numbers in the question, the integers which fall between 2 and 8 are 3, 4, 5, 6, and 7.
They lie between the integers -6 and +6.
Assuming that there is an equality sign between the two sevens, the equation is an example of the Abelian (or commutative) property of integers (or numbers) under addition.
-3 and 6 is one possible pair.
Answer: Between integers 6 and 7Math:5x = 3x + 135x -3x = 3x -3x + 132x = 13(2x) : 2 = (13) : 2Int (6) < (x = 6.5) < Int (7)