Excluding the numbers in the question, the integers which fall between 2 and 8 are 3, 4, 5, 6, and 7.
There are 9 integers between -8 and 2. These integers are -7, -6, -5, -4, -3, -2, -1, 0, and 1. The count includes both endpoints, but since -8 is not included and 2 is not included, we start counting from -7 to 1. Thus, the total is 9 integers.
8 and -8 8+(-8)=0 8-(-8)=16
8 and 9
there are 10 integers
8
There are 9 integers between -8 and 2. These integers are -7, -6, -5, -4, -3, -2, -1, 0, and 1. The count includes both endpoints, but since -8 is not included and 2 is not included, we start counting from -7 to 1. Thus, the total is 9 integers.
-8
8 and -8 8+(-8)=0 8-(-8)=16
There are 11 integers between -4 and 8.
8 and 9
2 & 6
NO. It depends on which you are subtracting from which. For example, the difference between 8 and 6 is 2 (8 - 6 = 2) but the difference between 6 and 8 is -2 (6 - 8 = -2).
NO. It depends on which you are subtracting from which. For example, the difference between 8 and 6 is 2 (8 - 6 = 2) but the difference between 6 and 8 is -2 (6 - 8 = -2).
I think you mean 'the sq rt of 48 lies between what 2 integers.' The answer is 6 and 7.
there are 10 integers
8 (8^2 = 64) and 9 (9^2 = 81)
8 and 9