Suppose the polygon has V vertices.Then sum of interior angles is (V - 2)*180 degrees = 1980 degrees => V - 2 = 1980/180 = 11 => V = 13 A polygon with V vertices has V*(V-3)/2 = 13*10/2 = 65 diagonals.
There are always 2 diagonals in any quadrilateral whether or not it is irregular or regular
An n sided polygon has n*(n-3)/2 diagonals.
It can be :- 1- a parallelogram 2- Square if diagonals are perpendicular and congruent 3- Rectangle if diagonals are congruent 4- Rhombus if diagonals are perpendicular
A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
Suppose the polygon has V vertices.Then sum of interior angles is (V - 2)*180 degrees = 1980 degrees => V - 2 = 1980/180 = 11 => V = 13 A polygon with V vertices has V*(V-3)/2 = 13*10/2 = 65 diagonals.
The formula which tells you the number of diagonals possible in a regular polygon is:the number of points (or sides), which we will call 'n', multiply by (n-3). Then divide the answer by 2.This will give you the number of diagonals.Formula: n X (n-3)/2ExamplesA square has four sides.4 X (4-3) = 2Divide 2 by 2 = 2So a square, a 4-sided polygon, has two diagonals.A pentagon has five sides5 X (5-3) = 10Divide 10 by 2 = 5So a 5-sided polygon has 5 diagonalsUsing the same formula we can calculate the number of diagonals of any regular polygon.e.g. 13-sides13 X (13-3) = 130Divide 130 by 2 = 65So a 13-sided polygon has 65 diagonals!If a polygon is irregular, meaning that its sides are of different lengths, and if all the points of the polygon are pointing outwards, the same formula holds true.But if the polygon is so irregular that some of its angles point inwards, there is no way of computing the number of diagonals because, in some irregular polygons, some potential diagonals may be impossible to reach from one point to the other without going outside the boundary of the polygon.
There are always 2 diagonals in any quadrilateral whether or not it is irregular or regular
ontrian
100 sided polygon has = n(n-3)/2 diagonals = 100(100-3)/2 = 4850 diagonals
An n sided polygon has n*(n-3)/2 diagonals.
The formula for finding the amount of diagonals in a polygon is n(n-3)/2. So 14(14-3)/2 = 77 Diagonals
The formula used to find the number of diagonals in a polygon is n(n-3)/2. 30 x 27/2 = 810/2 = 405 diagonals.
A polygon with n sides has 1/2*n*(n - 3) diagonals. So, for a polygon, with n = 12, there are 54 diagonals.
For an n-sided polygon, the number of diagonals is 1+2+3+....+(n-4)+2(n-3). For a nine-sided polygon, there are 1+2+3+4+5+2(6)=27 diagonals.
quadrilateral
It can be :- 1- a parallelogram 2- Square if diagonals are perpendicular and congruent 3- Rectangle if diagonals are congruent 4- Rhombus if diagonals are perpendicular