Q: How do you factor 125x3 minus 8?

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(2x - 1)(5x + 8)

no

You could factor this as a difference of squares, but because 8 is not a perfect square, you would wind up with radicals in your answer: x2 - 8 = (x + √8)(x - √8) = (x + 2√2)(x - 2√2)

(5x + y)(25x^2 - 5xy + y^2)

(x + 2)(x - 9)

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The answer is 383

(x + 1)(x - 8)

8(3x ^2 - 8)

(3x + 8)(3x - 8)

(x + 2)(x - 4)

(7x + 8)(7x - 9)

3(x - 8)

125x3 + 1 ???????? 53 * x3 + 1 ================?????

It is: (2x+3)(3x-8) when factored

(2x - 1)(5x + 8)

8(y - 1)(y^2 + y + 1)

(b + 8)(b - 1)