(5x - 2)(25x^2 + 10x + 4)
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(2x - 1)(5x + 8)
no
You could factor this as a difference of squares, but because 8 is not a perfect square, you would wind up with radicals in your answer: x2 - 8 = (x + √8)(x - √8) = (x + 2√2)(x - 2√2)
(5x + y)(25x^2 - 5xy + y^2)
-5 - 13 = -18