(2x - 1)(5x + 8)
no
You could factor this as a difference of squares, but because 8 is not a perfect square, you would wind up with radicals in your answer: x2 - 8 = (x + √8)(x - √8) = (x + 2√2)(x - 2√2)
(5x + y)(25x^2 - 5xy + y^2)
-5 - 13 = -18
The answer is 383
(x + 1)(x - 8)
8(3x ^2 - 8)
(3x + 8)(3x - 8)
(x + 2)(x - 4)
(7x + 8)(7x - 9)
3(x - 8)
125x3 + 1 ???????? 53 * x3 + 1 ================?????
It is: (2x+3)(3x-8) when factored
(2x - 1)(5x + 8)
(b + 8)(b - 1)
8(y - 1)(y^2 + y + 1)