if r=5z and 15z =3 then r=10y
r = 5z 15z = 3y (divide by 3 to both sides) 5z = y r = y
15z² - 22z - 5 = 0 → (5z + 1)(3z - 5) = 0
It would appear that r = y
15z +5x-30y = 5(x - 6y + 3z)
15z+5+6z=0 21z+5=0 z=-5/21
if r=5z and 15z =3 then r=10y
15z = 15 x 6 = 90
r = 5z 15z = 3y (divide by 3 to both sides) 5z = y r = y
15z² - 22z - 5 = 0 → (5z + 1)(3z - 5) = 0
if: r = 5z 15z = 3y then: z = y/5 r = 5(y/5) r = y
It would appear that r = y
Don't do the question immediately, read the sentence 3 times and visualize what is it saying. Its just like hitting you from the left to right brain and back to left brain again, but focus thinking on the right, its just confusing as it sounds but its just simplicity in a rather complex sentence if you did not read it carefully. Since R = 5Z then 15Z = 3Y then R = ? Since it means one R = 5Z 15Z = 3y, saying 3times the Y = 15Z So you want to find out R =?, 5Z = R, 10Z = 2Y so R = Y! :D
15z +5x-30y = 5(x - 6y + 3z)
15 percent 0 equals 0; 0 percent 15 equals 0. Both the above are true
If r = 5z, then 15z = 3y, then r = y. This can be solved easily by solving for z in the second equation and substituting into the first equation.
yes