If: -15z = 0 Then: z = 0
if r=5z and 15z =3 then r=10y
15z² - 22z - 5 = 0 → (5z + 1)(3z - 5) = 0
r = 5z 15z = 3y (divide by 3 to both sides) 5z = y r = y
(a + 2b)(a + 2b)
15z+5+6z=0 21z+5=0 z=-5/21
3z2 + 45z + 42 = 3(z2 + 15z + 14) = 3(z + 1)(z + 14).
2(3z - 5)(9z2 + 15z + 25)
If: -15z = 0 Then: z = 0
15z = 15 x 6 = 90
if r=5z and 15z =3 then r=10y
15z² - 22z - 5 = 0 → (5z + 1)(3z - 5) = 0
If r = 5z, then 15z = 3y, then r = y. This can be solved easily by solving for z in the second equation and substituting into the first equation.
if: r = 5z 15z = 3y then: z = y/5 r = 5(y/5) r = y
r = 5z 15z = 3y (divide by 3 to both sides) 5z = y r = y
5m
The other factor is 1.