In this type of problem you want to solve the value of the variable "v." We do it by isolating the v on one side of the equation. Remember whatever you do to one side you have to do to the other but you can do whatever you want.
-22 = 11v
Divide both sides by 11
-22/11 = 11v/11
Simplify this expression to get your answer.
-2 = v
10v2 = 11v - 7 10v2 - 11v = 11v - 11v - 710v2 - 11v + 7= -7 + 710v2 - 11v + 7 = 0This is in the standard form. There are many different ways to solve this, and I will use the 'completing the square' method.(10v2 - 11v + 7)/10 = 0/10v2 - (11/10)v + 7/10 = 0v2 - (11/10)v = -7/10v2 - (11/10)v + 121/400 = -7/10 + 121/400(v-(11/20))2 = (-280+121)/400(v-(11/20))2 = -159/400v-(11/20) = ±√(-159/400)v = (11±√(-159))/20v = (11±i√(159))/20Both of the roots are imaginary and do not cross the x-axis
louise 11V
13
Knights and Fighting by Henry the 11V
X +13 equals 22, X equals nine
5x4.4=22
34
-29
22/12
22 + 22
Well, darling, 5 times what equals 110? Let me do the math for you - it's 22. So, there you have it, 5 times 22 equals 110. Math doesn't lie, honey!
1 x 22, 2 x 11 = 22