2.015 is the same value as 2015/1000. 2015/1000=403/200 The simplest form of 2.015 is 403/200
I write 6 015 103 as 6 015 103.
0.015 as a decimal is equivalent to 0.015. This is because the number 0.015 does not need to be converted to a different form to represent it as a decimal. It is already in decimal form, with the decimal point separating the whole number (0) from the decimal fraction (015).
Since 015 = 15, 015 of 1% = 15 of 1% = 15% or 0.15
015% = 15% is equal to 0.15
1.5% written as a fraction in simplest form is 3/200
0.015 = 015/1000 = 15/1000 = 3/200
.015 as a fraction is 15/1000. In simplified form it is 3/200.
2.015 is the same value as 2015/1000. 2015/1000=403/200 The simplest form of 2.015 is 403/200
0.15 written as a fraction in simplest form is 3/20Explanation:0.15 is the same thing as 15 hundredths or 15/100. Using one of the laws of division, we can divide both the top and the bottom of the fraction by the same amount to get an equivalent fraction. Dividing by the greatest common factor (GCF) will get you the fraction in simplest form. The GCF is 5 so when we divide both sides by 5 we get 3/20.That would be 3/20
I write 6 015 103 as 6 015 103.
Since 015 = 15, 015 of 1% = 15 of 1% = 15% or 0.15
015% = 15% is equal to 0.15
0.015
0.33 = 1.5% X; X is the number 0.33 = 0.015 X X = 22 Above answer is absolutely correct. More detail follows: Below, Let "W" stand for "What".... Now, state your question in equation form. .33 = 1.5% * W Then convert the % to decimal form .33 = (1.5 * .01) * W And, simplify that decimal form .33 = .015 * W To solve for W, divide both sides by .015 .33 / .015 = W Lastly, simplify that fraction 22 = W So, your answer is .33 is 1.5 percent of 22.
15/100. 1.5/1000 .15/10000 .015/100000 .0015/1000000 .00015/10000000 .000015/100000000 .0000015/1000000000 Yeahhh.
Its actually quite easy, technically, it's written as 0.5p or you can write it as a fraction. There used to be half a penny coin too so maybe, if you found out the calculational term for that, it should give you an 100% accurate answer although this is quite close.