Average acceleration = (change in speed) divided by (time for the change) =(15 - 0) / (5) = 15/5 =3 meters per second2
Average acceleration = change in speed/time for the change = 15/5 = 3 meters per second2 .
position final = position initial + (speed initial)(time) + .5(acceleration)(time^2) 0=300 + 0(x) +.5(-9.807)(x^2) 0=300 + 0 + -4.9035(x^2) -300=-4.9035(x^2) -300 / -4.9035 = x^2 61.18 = x^2 x = 7.82 seconds That is to assume that the initial speed is 0. This is incorrect. The initial distance is in feet, 300 feet, but the rate of acceleration is in meters per second squared, (-9.807 meters per second squared). To get the correct answer, the units of measurement must match, either feet or meters. The correct answer is 4.32 seconds.
To solve that, you would divide 6 into 5.E.g. -5/6 = 0.833333333 meters per second.
Using one of the three laws of mechanical motion : v2 = u2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, s is the distance. Then, 0 = 202 + 2 x (-1)s : 2s = 400 : s =200 meters. The puck will travel 200 meters.
The speed of the plane after 10 seconds of acceleration at 15 m/sĀ² would be 150 meters per second. This is calculated by multiplying the acceleration (15 m/sĀ²) by the time (10 seconds).
Metres per second squared (m/s^2). Acceleration is the amount by which speed increases. Since velocity is measured in metres per second, and acceleration is change in velocity over time (dv/dt), acceleration is measured in metres per second per second, or metres/second squared, m/s², or meter per squared second. So if in t=0 a body moves at 5 meters per second, and in t=1 it is moving at 10 meters per second, it is accelerating, and the acceleration rate is 5 meters per second per second. Thus, 5(m/s)/s = 5 m/s²
m/s², or meter per squared second. Acceleration is the amount by which speed increases. So if in t=0 a body moves at 5 meters per second, and in t=1 it is moving at 10 meters per second, it is accelerating, and the acceleration rate is 5 meters per second per second. Thus, 5(m/s)/s = 5 m/s²
Average acceleration = (change in speed) divided by (time for the change) =(15 - 0) / (5) = 15/5 =3 meters per second2
Average acceleration = change in speed/time for the change = 15/5 = 3 meters per second2 .
position final = position initial + (speed initial)(time) + .5(acceleration)(time^2) 0=300 + 0(x) +.5(-9.807)(x^2) 0=300 + 0 + -4.9035(x^2) -300=-4.9035(x^2) -300 / -4.9035 = x^2 61.18 = x^2 x = 7.82 seconds That is to assume that the initial speed is 0. This is incorrect. The initial distance is in feet, 300 feet, but the rate of acceleration is in meters per second squared, (-9.807 meters per second squared). To get the correct answer, the units of measurement must match, either feet or meters. The correct answer is 4.32 seconds.
Something that has a constant acceleration of 13.3 per second squared
The equation of motion is V = V0 + a*t V - velocity V0 - initial velocity a - acceleration t - time V0 = 0, a = 6, t = 5 V = 0+6*5 V = 30 meters per second. The mass is irrelevant for the question.
All objects will fall at the same rate of speed in a vacuum chamber, which is approximately 9.8 meters per second squared (m/s^2) or about 22 miles per hour (35 kilometers per hour) after one second of free fall.
Acceleration(average) = change in velocity/change in time a = 40 m/s - 0 m/s/2.4 s = 17 m/s2 =======
To solve that, you would divide 6 into 5.E.g. -5/6 = 0.833333333 meters per second.
No. The speed of sound in copper is well below that.