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What is the average acceleration of a car that changes speed from 0 meters per second to 15meters per second in 5 second?
Average acceleration = (change in speed) divided by (time for the change) =(15 - 0) / (5) = 15/5 =3 meters per second2
What is the average acceleration of a car that changes speed from 0 meters per second to 15 meters per second in 5seconds?
Average acceleration = change in speed/time for the change = 15/5 = 3 meters per second2 .
How long to fall 300 feet?
position final = position initial + (speed initial)(time) + .5(acceleration)(time^2) 0=300 + 0(x) +.5(-9.807)(x^2) 0=300 + 0 + -4.9035(x^2) -300=-4.9035(x^2) -300 / -4.9035 = x^2 61.18 = x^2 x = 7.82 seconds That is to assume that the initial speed is 0. This is incorrect. The initial distance is in feet, 300 feet, but the rate of acceleration is in meters per second squared, (-9.807 meters per second squared). To get the correct answer, the units of measurement must match, either feet or meters. The correct answer is 4.32 seconds.
How do you convert five sixth into 0 point 83 meters per second for your physics homework?
To solve that, you would divide 6 into 5.E.g. -5/6 = 0.833333333 meters per second.
A hockey puck moves with velocity of 20meters per second If the friction of the ice retards the puck 1 meters per second squared How far will it go before it stops?
Using one of the three laws of mechanical motion : v2 = u2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, s is the distance. Then, 0 = 202 + 2 x (-1)s : 2s = 400 : s =200 meters. The puck will travel 200 meters.
