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Using one of the three laws of mechanical motion : v2 = u2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, s is the distance. Then,

0 = 202 + 2 x (-1)s : 2s = 400 : s =200 meters.

The puck will travel 200 meters.

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Q: A hockey puck moves with velocity of 20meters per second If the friction of the ice retards the puck 1 meters per second squared How far will it go before it stops?
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