2
To find the equivalent decimal number for the binary number 110101001, you can use the positional value method. Each digit represents a power of 2, starting from the rightmost digit, which is 2^0. In this case, you calculate: (1 \times 2^8 + 1 \times 2^7 + 0 \times 2^6 + 1 \times 2^5 + 0 \times 2^4 + 1 \times 2^3 + 0 \times 2^2 + 0 \times 2^1 + 1 \times 2^0), which equals 256 + 128 + 0 + 32 + 0 + 8 + 0 + 0 + 1 = 421. Thus, 110101001 in binary is equivalent to 421 in decimal.
The binary code 0111 0011 can be converted to its decimal equivalent by calculating the value of each bit. Starting from the right, the values are 2^0, 2^1, 2^2, and so on. This gives us: (0 \times 2^7 + 1 \times 2^6 + 1 \times 2^5 + 1 \times 2^4 + 0 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 1 \times 2^0 = 0 + 64 + 32 + 16 + 0 + 0 + 2 + 1), which equals 115. Thus, the decimal equivalent of 0111 0011 is 115.
To find the base 10 representation of the binary number 1100110, first convert it to decimal. The binary number 1100110 equals (1 \times 2^6 + 1 \times 2^5 + 0 \times 2^4 + 0 \times 2^3 + 1 \times 2^2 + 1 \times 2^1 + 0 \times 2^0), which calculates to (64 + 32 + 0 + 0 + 4 + 2 + 0 = 102). Now, raising this to the power of two, (102^2) equals 10,404.
0 to the power of 2 is 0, because to times 0 equals 0.
The binary number 01110 in base 10 can be calculated by multiplying each digit by 2 raised to the power of its position, starting from the right (position 0). This gives: (0 \times 2^4 + 1 \times 2^3 + 1 \times 2^2 + 1 \times 2^1 + 0 \times 2^0), which simplifies to (0 + 8 + 4 + 2 + 0 = 14). Therefore, 01110 in base 10 is 14.
100101 1 times 2^0 = 1 PLUS 0 times 2^1 = 0 PLUS 1 times 2^2 = 4 PLUS 0 times 2^3 = 0 PLUS 0 times 2^4 = 0 PLUS 1 times 2^5 = 32 EQUALS 37
The binary number 10000001 represents the value of 129 in base 10. This is calculated by taking each digit of the binary number, multiplying it by 2 raised to the power of its position (from right to left, starting at 0). Specifically, (1 \times 2^7 + 0 \times 2^6 + 0 \times 2^5 + 0 \times 2^4 + 0 \times 2^3 + 0 \times 2^2 + 0 \times 2^1 + 1 \times 2^0 = 128 + 1 = 129).
0
1.75 times
because when you multiply 2 by 0 you're actually saying what is 2 zero times so it would be zero
0 to the power of 2 is 0, because to times 0 equals 0.
The binary number 01110 in base 10 can be calculated by multiplying each digit by 2 raised to the power of its position, starting from the right (position 0). This gives: (0 \times 2^4 + 1 \times 2^3 + 1 \times 2^2 + 1 \times 2^1 + 0 \times 2^0), which simplifies to (0 + 8 + 4 + 2 + 0 = 14). Therefore, 01110 in base 10 is 14.
0
0
12b2 - 8b = 0 4b(3b-2) = 0 4b = 0 and 3b-2 = 0 4b = 0 and 3b = 2 b = 0 and 2/3
The answer to this mathematical equation is zero(0).
The sequence "110101" is a binary number, which is a base-2 numeral system that uses only two digits: 0 and 1. In decimal (base-10), this binary number converts to 53. Each digit represents a power of 2, starting from the rightmost digit, which represents (2^0), and moving left. Therefore, it can be calculated as (1 \times 2^5 + 1 \times 2^4 + 0 \times 2^3 + 1 \times 2^2 + 0 \times 2^1 + 1 \times 2^0).