200 L
You can't convert that. * mm is a unit of length. * l (liter) is a unit of volume.
Area of rectangle = l X b . Here , l=13 cm . 1 cm =10 mm. so, 13 cm =130 mm. b=86 mm. NOw , area = 11180 mm sq.
As asked, the question is nonsense as:* millimeters are a measure of length; whereas* liters are a measure of volume.However, if you meant milliLITERS or CUBIC millimeters, then:1 l = 1000 ml→ 7.2 l = 7.2 x 100 ml = 7200 mlor:1 cm = 10 mm→ 1 cu cm = 1 cm x 1 cm x 1 cm = 10 mm x 10 mm x 10 mm = 1000 cu mm1 ml = 1 cu cm → 1 l = 1000 cu cm→ 1 l = 1000 x 1000 cu mm = 1000000 cu mm→ 7.2 l = 7.2 x 1000000 cu mm = 7200000 cu mm
(L+W) + (L+W) divided by 4
1.2 l subtracted from 200 mm = -198.8
1.2 L is more than 200 mm and I am not sure what you intended to ask about.
There are 1,000 mm in a L.
200 L
Rainfall of 100 mm means 100 mm depth of rain falls over any area. 1 cu m = 1,000 l 1,000 mm = 1 m Volume = area x depth = 200 sq m x 100 mm = 200 sq m x 100 ÷ 1,000 m = 20 cu m = 20 x 1,000 l = 20,000 litres
200 L = 200 000 mLTo convert from L to mL, multiply by 1000.
You can't convert that. * mm is a unit of length. * l (liter) is a unit of volume.
Flexible steel wire rope (FSWR) To calculate the SWL in kilograms of FSWR square the rope diameter (D) in millimetres (mm) and multiply by 8. Formula: SWL (kg) = D2(mm) x 8 For example: Rope dia (D) = 12 mm SWL(kg) =D2 (mm)x8 = D (mm) x D (mm) x 8 = 12 x 12 x 8 = 1152 kg SWL (t) = 1.15 tonnes The above equation can be reversed to calculate the diameter (D) in millimetres of FSWR needed to lift a given load. To do this, divide the load (L) in kilograms by 8 and find the square root of the result. Formula: D(mm) = √L(kg) 8 For example: Load = 1152 kg D (mm) = √1152 ÷ 8 = √144 = 12 (mm) Therefore a FSWR sling of at least 12 mm in diameter is required to lift a 1152 kg load for a straight lift.
1.2 l - 200 m = -198.8
It is 200 L.
The bore of a 2.8 L is 86.0 mm. The stroke of a 2.8 L is 79 mm. When it comes to 2.8 L, it refers to an engine with an estimate 2,753 cc.
0.05 L