I assume you want to solve for x. The idea is to get the "x" isolated on one side of the equation. To do this, first subtract 6 from both sides (left and right of the equal sign). This will get rid of the 6 on the left side. Next, in the result, divide both sides by 10 - this will get rid of the 10 on the left side.
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6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.
x + 13x + 10x = 50 - 6
6-x+12 = 10x+7 6+12-7 = 10x+x 11 = 11x x = 1
-6x-6 -or- -6(x+1)
6-3x = 5x-10x+2 4 = 8x-10x 4 = -2x x = -2