10x-7y = -6 5x+7y = 81 Add both equations to eliminate y: 15x = 75 Divide both sides by 15 to find the value of x: x = 5 Substitute the value of x into the original equations to find the value of y: Therefore: x = 5 and y = 8
if: 2x + 6 = -6 then: 2x = -12 x = -6 if: 5x + 7y = 1 then: 5(-6) + 7y = 1 7y = 31 y = 31/7
x + 13x + 10x = 50 - 6
6-x+12 = 10x+7 6+12-7 = 10x+x 11 = 11x x = 1
y is the variable
10x-7y = -6 5x+7y = 81 Add both equations to eliminate y: 15x = 75 Divide both sides by 15 to find the value of x: x = 5 Substitute the value of x into the original equations to find the value of y: Therefore: x = 5 and y = 8
if: 2x + 6 = -6 then: 2x = -12 x = -6 if: 5x + 7y = 1 then: 5(-6) + 7y = 1 7y = 31 y = 31/7
5y+8 = 7y-6 5y-7y = -6-8 -2y = -14 y = 7
x + 13x + 10x = 50 - 6
6-x+12 = 10x+7 6+12-7 = 10x+x 11 = 11x x = 1
y is the variable
3x + 7y = 3*x + 7*y = 3*6 + 7*4 = 18 + 28 = 46
X equals 6
-6x-6 -or- -6(x+1)
T = 3x + 7y; x = 4; y = 6T = 3x + 7y (substitute 4 for x, and 6 for y)T = 3(4) + 7(6) = 12 + 42 = 54
y=-10x-4
Yes, they are. If you solve 2x + 7y = 6 for y, you get y = (-2x + 6) / 7. If you solve 7y + 2x + 6 = 0 for y, you get y = (-2x - 6) / 7. As you can see, both equations have the same slope. Therefore they are parallel. You can punch those equations into a graphing calculator and visually verify that they are indeed parallel.