y2 + 10z - 10y - yz = y2 - 10y - yz + 10z = y(y - 10) - z(y - 10) = (y - 10)(y - z)
Ten z plus one, or ten z plus ten. That depends on where you had parentheses in the original expression: (10 * z) +1 = 10z + 110 * (z + 1) = 10z + 10
4
What is the number of integral solution to x plus y plus z equals 100?
-6z 2 = 3z+ 4z+28 -6z+2 +3z = 3z+ 4z +28 +4z -6z+4z+2 = 3z+ 28 -10z+2 -3z= 28 - 2 -10z + -3z = 26 -13z/13 = 26/-13 z = -2
y2 + 10z - 10y - yz = y2 - 10y - yz + 10z = y(y - 10) - z(y - 10) = (y - 10)(y - z)
Ten z plus one, or ten z plus ten. That depends on where you had parentheses in the original expression: (10 * z) +1 = 10z + 110 * (z + 1) = 10z + 10
11z+√(4z)+√(10z)=11z+√(10z)+2*√(z)
In algebra it is simply 10z
4
What is the number of integral solution to x plus y plus z equals 100?
-6z 2 = 3z+ 4z+28 -6z+2 +3z = 3z+ 4z +28 +4z -6z+4z+2 = 3z+ 28 -10z+2 -3z= 28 - 2 -10z + -3z = 26 -13z/13 = 26/-13 z = -2
The equation 7 x + 14 y + 10 z = 98001 has infinite solutions. For any x and y we can have a z which satisfies this equation. For example, if we choose x=1 and y=1 then z=9798 satisfies. To have a specific solution there must be three equations for three unknowns (x,y,z), which can be solved simultaneously.
To find the LCM, you first need to express the numbers as the product of their prime factors. In this case: 10z = 2x5xz 20x = 2x2x5xz The next step is to identify the HCF. In this case that's 2x5xz = 10z. Then you multiply the numbers together and divide by the HCF: 10z x 20z/10z = 20z Thus the LCM of 10z and 20z is 20z.
Since 20z is a multiple of 10z, it is automatically the LCM of this problem.
Given x=k1y and x=k2/z x=125 ,y=5 then k1=25 x=125 , z=4 then k2=125(4)=500 If y=4 ,z=5 then x=25y = 100
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