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The equation
7 x + 14 y + 10 z = 98001
has infinite solutions. For any x and y we can have a z which satisfies this equation.
For example, if we choose x=1 and y=1 then z=9798 satisfies.
To have a specific solution there must be three equations for three unknowns (x,y,z), which can be solved simultaneously.
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Solve for z 11y-10z x 6m?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals".
If 15x's equals 20y's and 16y's equals 10z's then 6x's equals how many z's?
To solve this problem, we first need to establish the relationship between x, y, and z. From the given information, we have 15x = 20y and 16y = 10z. To find the relationship between x and z, we can substitute y from the first equation into the second equation. By doing this, we get 16(15/20)x = 10z, which simplifies to 12x = 10z. Therefore, 6x would equal 5z.
What is the product of 10 and z?
In algebra it is simply 10z
How many ways are there to make a pound using only 50p a 20p and a 10p?
To make a pound using only 50p, 20p, and 10p coins, we can set up a linear Diophantine equation: 50x + 20y + 10z = 100, where x, y, and z are the number of each type of coin used. We can then use techniques such as generating functions or modular arithmetic to solve this equation and find the number of ways to make a pound. The solution will involve finding the integer solutions to the equation within a certain range, as there are constraints on the number of each type of coin available.
How many ways are there to make 14 cents?
The coins we know are:A penny - 1 centA nickel - 5 centsA dime - 10 centsA quarter - 25 centsLet x denote the number of pennies, y denote the number of nickels, z denote the number of dimes and w denote the number of quarter.We can set up the expression this way:x + 5y + 10z + 25w = 14But since we want to make 14 cents, quarters are not considered to be the part of the combination, so we write:x + 5y + 10z = 14There is no quick way to work out this problem. All you need to do is to work by trials.If we have y = 0 nickels and z = 1 dime, then the remaining choice is 4 pennies to make 14 cents.If we have y = 2 nickels and z = 0 dimes, then the remaining choice is also 4 pennies.If we have y = 1 nickel and z = 0 dimes, then the remaining choice is 9 pennies.If y = z = 0 of these coins - nickels and dimes - , then we can make 14 cents by 14 pennies.So there are 4 ways to form 14 cents.
