-57. first you subtracted 89, then you subtracted 80 (9 less than 89), then u subtracted 71 (9 less than 80), then you subtracted 62 (9 less than 71), so next you subtract 53 which is 9 less than 62. and -4-53=-57
333 + 110 = 390 + 53
34 - x = (53 - x)/2 68 - 2x = 53 - x x = 15 giving required fraction 19/38 The target numerator, in examples such as this, will be Old Denominator minus Old Numerator, ie 53-34 = 19
The subtrahend is subtracted from the minuend
188 subtracted by 84 = 104
110-53 = 57
99
58.3
Let x be the volume of the 53% solution and y be the volume of the 97% solution. The total volume will be x + y = 110 ml. The equation for the concentration is 0.53x + 0.97y = 0.65(110). Solving these two equations simultaneously gives x = 50 ml of the 53% solution and y = 60 ml of the 97% solution.
106
-57. first you subtracted 89, then you subtracted 80 (9 less than 89), then u subtracted 71 (9 less than 80), then you subtracted 62 (9 less than 71), so next you subtract 53 which is 9 less than 62. and -4-53=-57
(8/11)-(14/110) = 0.6
333 + 110 = 390 + 53
95 to 110
Trailer 53' - 110" high - 2 rows of 15 stacked 18 high for a total of 540 pallets
-100
Trailer 53' - 110" high - 2 rows of 15 stacked 18 high for a total of 540 pallets