4(3b - 5) < -31 + 12b12b - 20 < -31 + 12b, this is not true because -20 > - 31, so that the solution for the given inequality does not exist.
b = 6
(b + 8)(b + 4)
No, it is not.
A=12b+3 A=-2b--4
4(3b - 5) < -31 + 12b12b - 20 < -31 + 12b, this is not true because -20 > - 31, so that the solution for the given inequality does not exist.
-9/4b -10/3b =-67/6 9/4b +10/3b = 67/6 27/12b + 40/12b = 67/6 67/12b =67/6 12b = 6 b = 6/12 b=1/2
6a -12b + 30 = 6 (a - 2b + 5)
15b + 13c - 12b + 10c + 8 = 3b + 23c + 8
b = 6
(b+8)(b+4)
(b + 8)(b + 4)
156abc
No, it is not.
A=12b+3 A=-2b--4
It is: 4b+16 simplified
(b + 8)(b + 4)