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Q: What is 12r-15s-r plus 3s?

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333,333,333,333,333 trillion

2/3.

Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0

It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0

(3*3+3)/3=4

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135=3s +15 120=3s 40=s

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3s + 4t + 2s + 5s + 6tGroup all of the like 's' terms & 't' terms together:(3s+2s+5s) + (4t + 6t)10s + 10t or 10(s+t)

You have to combine equal terms. -5r-9s+9r+3s-6 = -5r+9r-9s+3s-6 = 4r-6s-6

2s + s + 12 = 132 3s + 12 = 132 3s = 132 - 12 3s = 120 s = 40

Simplified its 12r+3s

2s + s + 12 =132 ie 3s = 132 -12 3s = 120 s = 40

-3s*4p+-4s*3p -12sp+-12sp -24sp

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