No. 133+7 =140 which is divisible by 7, so 133 is also divisible by 7. (It is 7 * 19.)
No.
They are both divisible by 1 and 19.
Yes.
567 is divisible by 9. 32 and 133 are not.
665 is divisible by 1, 5, 7, 19, 35, 133, 665.
No, because if you add the three digits together, you get 7 which isn't divisible by 3
Not evenly. But it is 44.33333 (repeating) or 44 1/3.
D
No. 1,197 is divisible by these numbers: 1, 3, 7, 9, 19, 21, 57, 63, 133, 171, 399, 1197.
Well because it can be divide by 19 and 7 by 1 and its self. A prime number can only be divided by 1 and its self. In this case the number 133 is not only divisible by 1 and itself it is also divisible by 19 ,7 which makes it composite.
No, its factors are: 1, 7, 19, 133.A prime number can be divided, without a remainder, only by itself and by 1. For example, 17 can be divided only by 17 and by 1. so no