1368 = MCCCLXVIII
1368 = 2 * 2 * 2 * 3 * 3 * 19
The number 1368 can be divided evenly by several numbers, including 1, 2, 3, 4, 6, 8, 12, 17, 24, 34, 51, 68, 102, 136, 204, 289, 408, 578, 867, and 1156. These are factors of 1368 because they divide into 1368 without leaving a remainder.
English year of Bengali year 1368 is 1961
841 + 527 = 1368
12% of 1368= 12% * 1368= 0.12 * 1368= 164.16
The multiples of 171 (which are infinite) are all divisible by 171 , including these: 171, 342, 513, 684, 855, 1026, 1197, 1368, 1539 . . .
1368 = MCCCLXVIII
1248, 1368, 2568 - the question needs to be more specific.
The LCM is 1368.
A single number, such as 1368, is not sufficient to determine a rule.
1368 = 2 * 2 * 2 * 3 * 3 * 19
1368 = 2 * 2 * 2 * 3 * 19
The LCM is 1368.
It is 1368.
Since it must be divisible by both 8 and 9, and the LCM of 8 and 9 is 72, the number must be divisible by 72. Since it is a 4 digit number, I'll assume the highest digit is not zero, so the number must be greater than 1000 and less than 10000 and divisible by 72. The first number that satisfies this is 18 x 72 = 1296. Then 19 x 72 = 1368. You can keep going and eliminate the ones with repeated digits. Here are several: 1296, 1368, 1584, 1728, 1872, 2016, 2160, 2304, 2376, 2736, 3024, 3096, ...., 9072, 9216, 9360, 9432, 9504, 9576, 9648, 9720, 9864
All multiples of 456, which is an infinite number, including 456, 912, 1368, 1824, 2280, 2736 . . .