3/7 = 0.428571428571428
To find the prime factors, start with the obvious ones. 4914 is even so divide it by 2 and we get 2457. The digit sum of this is 9, so divide by 9 (3x3) and get 273. The digit sum divides by 3 so divide by 3 and get 91, which is 13x7. So in total we have 2, 3, 3, 3, 7 and 13 as the prime factors of 4914
Divide by 3, 7 and 13. 1, 3, 7, 13, 21, 39, 91, 273
7 + 9 + 11 = 27. Divide by 3. = 9.
To find the units digit of (27^{27}), we can look at the units digit of (27), which is (7). We then need to find the units digit of (7^{27}). The units digits of the powers of (7) cycle every four terms: (7^1 = 7), (7^2 = 49) (units digit (9)), (7^3 = 343) (units digit (3)), and (7^4 = 2401) (units digit (1)). Since (27 \mod 4 = 3), the units digit of (7^{27}) is the same as that of (7^3), which is (3). Thus, the units digit of (27^{27}) is (3).
(51/3) / (13/4) = (16/3) / (7/4) = (16/3) * (4/7) = 64/21
To find the prime factors, start with the obvious ones. 4914 is even so divide it by 2 and we get 2457. The digit sum of this is 9, so divide by 9 (3x3) and get 273. The digit sum divides by 3 so divide by 3 and get 91, which is 13x7. So in total we have 2, 3, 3, 3, 7 and 13 as the prime factors of 4914
Divide by 3, 7 and 13. 1, 3, 7, 13, 21, 39, 91, 273
728 Divide by two. 364,2 Divide by two. 182,2,2 Divide by two. 91,2,2,2 Divide by seven. 13,7,2,2,2 Stop.
To find the least positive 4-digit multiple of 7, we need to divide 1000 by 7 to get the closest whole number, which is 142.857. We then multiply this whole number by 7 to get 994, which is the largest 3-digit multiple of 7. Therefore, the least positive 4-digit multiple of 7 is 1001.
The smallest 3-digit multiple of 7 is 105 = 15*7 The largest 3-digit multiple of 7 is 994 = 142*7 So there are 142-14 = 128 3-digit multiples of 7, ie 128 3-digit numbers that are divisible by 7.
7 + 9 + 11 = 27. Divide by 3. = 9.
2506 2506 is divisible by 7. (6 is 3 times of 2; 2+5+0+6=13; 5=6–1)
All 2 digit numbers are divisible by 7: it is simply that some of the quotients are not whole numbers. 10/7 = 1 3/7 99/7 = 14 1/7 So the number of 2-digit numbers which are evenly divisible by 7 are 14-1 = 13.
To find the units digit of (27^{27}), we can look at the units digit of (27), which is (7). We then need to find the units digit of (7^{27}). The units digits of the powers of (7) cycle every four terms: (7^1 = 7), (7^2 = 49) (units digit (9)), (7^3 = 343) (units digit (3)), and (7^4 = 2401) (units digit (1)). Since (27 \mod 4 = 3), the units digit of (7^{27}) is the same as that of (7^3), which is (3). Thus, the units digit of (27^{27}) is (3).
To determine how many times the digit 7 goes into 87, we need to divide 87 by 7. Performing the division, we find that 7 goes into 87 12 times with a remainder of 3. Therefore, the digit 7 goes into 87 twelve times.
The highest four digit number with 13 and 7 as common factors is 9919, which is equal to 13 x 763 and 7 x 1417.
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