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What are the prime factors of 4914?
To find the prime factors, start with the obvious ones. 4914 is even so divide it by 2 and we get 2457. The digit sum of this is 9, so divide by 9 (3x3) and get 273. The digit sum divides by 3 so divide by 3 and get 91, which is 13x7. So in total we have 2, 3, 3, 3, 7 and 13 as the prime factors of 4914
How do you find all of the factors of 273?
Divide by 3, 7 and 13. 1, 3, 7, 13, 21, 39, 91, 273
What is the average of 7 and 9 and 11?
7 + 9 + 11 = 27. Divide by 3. = 9.
What is the units digit of 27 to the 27th power?
To find the units digit of (27^{27}), we can look at the units digit of (27), which is (7). We then need to find the units digit of (7^{27}). The units digits of the powers of (7) cycle every four terms: (7^1 = 7), (7^2 = 49) (units digit (9)), (7^3 = 343) (units digit (3)), and (7^4 = 2401) (units digit (1)). Since (27 \mod 4 = 3), the units digit of (7^{27}) is the same as that of (7^3), which is (3). Thus, the units digit of (27^{27}) is (3).
How do you divide 5 1 3 and 1 3 4?
(51/3) / (13/4) = (16/3) / (7/4) = (16/3) * (4/7) = 64/21
