156 = 2 x 2 x 3 x 13.
156 = 2 x 2 x 3 x 13
Expressed as a product of its prime factors, 156 is equal to 22 x 3 x 13. The only prime factors for 156 are 3 and 13. Though these are not used in the same equation.
X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers
156 = 2 x 2 x 3 x 13, 504 = 2 x 2 x 2 x 3 x 3 x 7 so GCF is 2 x 2 x 3 ie 12.
2 x 2 x 3 x 13 = 156
156 = 2 x 2 x 3 x 13.
156 = 2 x 2 x 3 x 13
156 x 2 = 312
12 x 13 = 156 How to find the answer: If x is the first integer, then x+1 is the next consecutive integer. so x(x+1) = 156 or x^2 + x -156 =0 solve the quadratic equation for x.
2 x 2 x 3 x 1313 * 2 * 2 * 3 = 156
156 2 x 78 2 x 39 13 x 3 prime factorization 2,2,13,3
Factors of 156: 1, 2, 3, 4, 6, 12, 13, 26, 39, 52, 78, and 156 Prime Factorization of 156: 2 x 2 x 3 x 13
1 x 156, 2 x 78, 3 x 52, 4 x 39, 6 x 26, 12 x 13 = 156
1 x 156, 2 x 78, 3 x 52, 4 x 39, 6 x 26, 12 x 13 = 156
The prime factorization of 156 is 2^2 x 3 x 13. This means that 156 can be expressed as the product of these prime numbers. To find the prime factorization, you would first divide 156 by the smallest prime number, 2, then continue dividing by prime numbers until you reach the prime factorization.
Expressed as a product of its prime factors, 156 is equal to 22 x 3 x 13. The only prime factors for 156 are 3 and 13. Though these are not used in the same equation.