12 x 13 = 156
How to find the answer: If x is the first integer, then x+1 is the next consecutive integer. so x(x+1) = 156 or x^2 + x -156 =0 solve the quadratic equation for x.
The numbers are 6 and 8.
You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
There are two consecutive even integers that equal -298: -150 and -148.
It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.
Divide the sum of the two consecutive odd integers by 2: 156/2=78. The two consecutive odd integers will be one more and one less than 78, so the smaller will be 77 and the larger will be 79.
X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers
what is the formula to use to solve the product of two consecutive odd integers
The two consecutive odd integers having a product of 99 are 9 and 11.
I think you mean consecutive even integers: 20 & 22
You need to look for 2 numbers which have a product of 156 and a difference of 1. First 156 can be written as a product of it's prime factors: 156 = 22 x 3 x 13. From this you can see that 22 x 3 = 12 and hence 12 x 13 = 156.
The product of 2 consecutive positive number is 48. Find the 2 numbers
The numbers are 6 and 8.
The numbers are 13 and 14.
It is 23.
13 & 15
-7 multiplied by -8 = 56