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If 24 counters are the whole set how many are five-eighths of the set?
24 counters = 8/824 * 5/8 = 15
How many blue counters must be added so that the ratio of yellow counters to total counters is 1 to 6?
Let the number of Yellow counters you already have is Y Let the number of non-yellow counters you already have is Z Then the current ratio of Yellow counters to the total counters is Y : Y + Z Let the number of Blue counters you add be B After they have been added, the ratio of Yellow counters to the total counters is Y : Y + Z + B This is 1 : 6 Thus Y = 1 and Y + Z + B = 6 → Z + B = 5 Which means that for the Yellow counters you have you will have five times as many counters made up of whatever non-Yellow counters you originally had plus the Blue counters you added. Thus to find out how many Blue counters to add, take the number of Yellow counters, multiply it by 5 and subtract the number of non yellow counters you originally had. examples: You had 6 Yellow counters Add 6 × 5 - 0 = 30 Blue counters Which gives you 6 Yellow and 30 Blue counters → ratio Yellow : total counters = 6 : 30 + 6 = 6 : 36 = 1 : 6 You had 4 Yellow counters and 6 Red counters Add 4 × 5 - 6 = 14 Blue counters Which gives you 4 Yellow counters, 6 Red counters and 14 Blue counters → ratio Yellow : total counters = 4 : 6 + 14 + 4 = 4 : 24 = 1 : 6 You had 4 Yellow Counters, 2 Blue counters and 3 Red counters Add 4 × 5 - (2 + 3) = 15 Blue counters Which gives you 4 Yellow counters, 3 Red counters and 2 + 15 = 17 Blue counters → ratio Yellow : total counters = 4 : 3 + 17 + 4 = 4 : 24 = 1 : 6
What is the greatest number of counters you can place on this grid without four of them lying at the corners of a square?
15
How do you do parts and whole fraction practice?
If 15 counters are the whole set, how many are 3/5 of the set 5
What is 1 third of 21 counters?
7 counters.
