6x-14x+16=27+11 answer: 4
There must be some operators between 16 and 10 and also between 10x and 14x, please clarify
-x2-14x-45 = -(x2+14x+45) delta = 142-4*1*45=16 so x2+14x+45=(x-(-14+4)/2) (x-(-14-4)/2) = (x+5)(x+9) so -x2-14x-45 = -(x+5)(x+9)
14x2-7x2-16 7x2-16 (this can't be simplified any more)
x=4
((14x2-21x)/(24x-16))x((12x-8)/(42x-63))
-14x-7 = 35 -14x = 35+7 -14x = 42 x = -3
Unfortunately, limitations of the browser used by WA means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. The new question submitted is 16 + 10x = 14x -4 Transposing and collecting terms we have 10x - 14x = -4 -16 -4x = -20 x = 5
14x + 6 = 6 14x + 6 - 6 = 6 - 6 14x = 0 14x / 14 = 0 / 14 x = 0
-14x
(x - 16)(x + 2) x = 16 or -2
-11