5/8 = 25/40 2/5 = 16/40 25/40 + 16/40 = 41/40
5 16/25 as a decimal = 5.64
'Squared' & 'Square Root; are the inverse mathemtical functions. 5 (squared) = 25 square root of '25' is 5 Mathematically this would be written as Square ; 5 x 5 = 5^(2) = 25 Square Root ; sqrt(25) = 25^(1/2) = 25^(0.5) = 5 NB THis can be exteneded to 'cubes' and 'cube roots' e.g. 3 x 3 x 3 = 3^(3) = 27 curt(27) = 27^(1/3) = 27^(0.3333.....) - 3 And fourth power and fourth root. e.g. Fourth power ; 2 x 2 x 2 x 2 = 2^(4) = 16 Fourth root = (4th)rt(16) = 16^(1/4) = 16^(0.25) = 2 It can be exteneded to the 'nth power' and the 'nth root'. Where 'n' is any number.
1, 4, 16, 25 are all square numbers: 1^2, 2^2, 4^2, 5^2 1+1=2, 2+2=4, 4+1=5. I guess the next basis number is 5+2=7 (+1,+2,+1,+2,+1,...) So I would guess: 1 4 16 25 49 64 100 121 ...
(2/5)/(5/8) = (2/5)(8/5) = (2*8/5*5) = (16/25)
The factors of 16 are 1, 2, 4, 8, 16 while the factors of 25 are 1, 5, 25
16/25 - 10/25 = 6/25
5/8 = 25/40 2/5 = 16/40 25/40 + 16/40 = 41/40
16 2/3 = 3(16)+2= 50/2= 25/1 5/6 is not equal to 25.
x / (25/60) = 5/16 so x = 5/16 * 25/60 = 5/16 * 5/12 = 25/192
16/25 (4/5)2 = 4/5 x 4/5 = (4 x 4)/(5 x 5) = (42)/(52) = 16/25
16x^2 - 25 Recognise that both 16 and 25 are squared numbers, 16 = 4^(2) & 25 = 5^(2) Substituting 4^(2)x^(2) - 5^(2) = > (4x)^(2) - 5^(2) We now have two squared terms with a negative between them. NB two squared terms with positive does NOT factor. Factoring (4x - 5)(4x + 5)
16 8,2 4,2,2 2,2,2,2 2 x 2 x 2 x 2 = 2^4 = 16 25 5,5 5 x 5 = 5^2 = 25 27 9,3 3,3,3 3 x 3 x 3 = 3^3 = 27 2^4 x 3^3 x 5^2 = 10800, the LCM
The factors of 9 are: 1, 3, 9 The factors of 16 are: 1, 2, 4, 8, 16 The factors of 25 are: 1, 5, 25
(4/5)-2 = (5/4)2 = 25/16
5 and 2/5 x 2 and 3/8 5=25/5 and 2=16/8 25/5 and 2/5=27/5 , 16/8 and 3/8 = 19/8 27/5 x 19/8 = 513/40 =12 and 33/40
5 16/25 as a decimal = 5.64