16x^2 - 25
Recognise that both 16 and 25 are squared numbers, 16 = 4^(2) & 25 = 5^(2)
Substituting
4^(2)x^(2) - 5^(2) = >
(4x)^(2) - 5^(2)
We now have two squared terms with a negative between them.
NB two squared terms with positive does NOT factor.
Factoring
(4x - 5)(4x + 5)
16x2 - 25 = (4x + 5) (4x - 5)
16x2 - 25 = (4x + 5) ( 4x - 5)
5(u-5)
If you mean 5x^2 -125 then it is 5(x^2 -25) when factored
There is no standard form for an expression.
16x2 - 25 = (4x + 5) (4x - 5)
16x2 - 25 = (4x + 5) ( 4x - 5)
5(u-5)
16x2 + 40x + 25 = 16x2 + 20x + 20x + 25 = 4x(4x + 5) + 5(4x + 5) = (4x + 5)(4x + 5) = (4x + 5)2
25x-75y+25 = 25(x-3y+1)
If you mean 5x^2 -125 then it is 5(x^2 -25) when factored
That can be factored to (3x - 5)(3x - 5) or (3x - 5)2
There is no standard form for an expression.
(x + 5)2
(4x+5)(4x+5)
If you mean: b squared+b+25 then the given quadratic expression can't be factored because its discriminant is less than zero.
(4x + 5)(4x + 5)