-99
Instead of adding each digit in turn, acknowledge that there are 100 numbers to add, and then multiply that by the average of 1 and 100.Ie. 100×(1+100)÷2=100×101;÷2100×101;÷2=50×101=5050So, in short, the answer is: 5050
Come on! It’s 50: 101 divided by 2 equals 50.5 51x2= 102 so is too big to go into 101 50x2= 100 so it’s the closest you can get to 101 101-100=1 so it’s 50 and remainder 1, or... you could just do 101/2=50.5
100 times 101 divided by 2 is equal to 5,050.
1 +100 = 101 100 - 1 = 99 99 +1 = 100 100 times 100 =10000 10000 divide by 2 = 5050Ans:5050
-99
Instead of adding each digit in turn, acknowledge that there are 100 numbers to add, and then multiply that by the average of 1 and 100.Ie. 100×(1+100)÷2=100×101;÷2100×101;÷2=50×101=5050So, in short, the answer is: 5050
yes. 1+ 100= 101 2+99=101 3+98=101 4+97=101 5+96=101 and so on. then its 101 times 50= 5050
Come on! It’s 50: 101 divided by 2 equals 50.5 51x2= 102 so is too big to go into 101 50x2= 100 so it’s the closest you can get to 101 101-100=1 so it’s 50 and remainder 1, or... you could just do 101/2=50.5
Move the 2 in 102 up to be an exponent [10² = 100]: 101 - 10² = 1.
-99
Answer = 5,050. (n)( n+1)/2 where n = 100. (100 x 101) / 2 = 5,050
-99
Gauss's method was to find the sum of 1-100. He tried adding with pairs 1 + 100 = 101, 2 + 99 = 101 and so on. Each pairs was going to equal 101. Half of 100 is 50, 50 x 101 = 5,050.
101
1+2+3+4.....+100 = 101*50= 5050
IN his head, bitchez! Or in longer words: by noting 1+100=101, 2+99=101, ... , 50+51=101 50 pairs of numbers summing to 101, so 50x101 = 5050