If we have y=a(b)^t as the equation then take b from this equation case !: If b <1 then b=1-r r=1-b this r is the decay factor case 2:If b >1 then b=1+r r=b-1 this is the growth factor
It isnC0*A^n*b^0 + nC1*A^(n-1)*b^1 + ... + nCr*A^(n-r)*b^r + ... + nCn*A^0*b^n where nCr = n!/[r!*(n-r)!]
P=B×RB=P÷RR=P÷B
Let the sides be a,b,c,(opposite to BC,AC,AB): Let the angle be enclosed at vertex A.Let R be the length of the angle bisector.The formula to find R is:cb= R*R + ([{(c-b)(c-b)-2bc.(cos A-1)}^1/2]/c+b)^2.cb
Suppose you are given one angle A and the ratio is R so that the other two angles are B and BxR.Then: A + B + BxR = 180.B (1 + R) = 180 - Aso the answer is B = (180 - A) / (1 + R)e.g. you are given A=60 and R=2so B = (180 - 60) / (1 + 2) = 40 and the last angle is 80.
If we have y=a(b)^t as the equation then take b from this equation case !: If b <1 then b=1-r r=1-b this r is the decay factor case 2:If b >1 then b=1+r r=b-1 this is the growth factor
It isnC0*A^n*b^0 + nC1*A^(n-1)*b^1 + ... + nCr*A^(n-r)*b^r + ... + nCn*A^0*b^n where nCr = n!/[r!*(n-r)!]
To calculate resistance in parallel: 1/R = 1/A + 1/B + 1/C + 1/D ... where R is the final result, and A, B, C... are the individual resistances. For two resistances A and B, you can simply calculate (A x B) / (A + B).
T r+1 = (n / r) (a ^n-r) x (b)^r
For brevity, (since only one 'move' is possible at any one time), the following sequence should solve the game; where R=Red and B=Blue: R B B R R R B B B B R R R R B B B B R R R B B R
these r maths problems they r quite hard
P=B×RB=P÷RR=P÷B
cube = a 3rectangular prism = a b cirregular prism = b hcylinder = b h = pi r 2 hpyramid = (1/3) b hcone = (1/3) b h = 1/3 pi r 2 hsphere = (4/3) pi r 3ellipsoid = (4/3) pi r1 r2 r3
1 rotten apple in every barrel
Let the sides be a,b,c,(opposite to BC,AC,AB): Let the angle be enclosed at vertex A.Let R be the length of the angle bisector.The formula to find R is:cb= R*R + ([{(c-b)(c-b)-2bc.(cos A-1)}^1/2]/c+b)^2.cb
b***h running after tony
Suppose you are given one angle A and the ratio is R so that the other two angles are B and BxR.Then: A + B + BxR = 180.B (1 + R) = 180 - Aso the answer is B = (180 - A) / (1 + R)e.g. you are given A=60 and R=2so B = (180 - 60) / (1 + 2) = 40 and the last angle is 80.