R & B stands for rythem and blues
If we have y=a(b)^t as the equation then take b from this equation case !: If b <1 then b=1-r r=1-b this r is the decay factor case 2:If b >1 then b=1+r r=b-1 this is the growth factor
It isnC0*A^n*b^0 + nC1*A^(n-1)*b^1 + ... + nCr*A^(n-r)*b^r + ... + nCn*A^0*b^n where nCr = n!/[r!*(n-r)!]
P=B×RB=P÷RR=P÷B
Let the sides be a,b,c,(opposite to BC,AC,AB): Let the angle be enclosed at vertex A.Let R be the length of the angle bisector.The formula to find R is:cb= R*R + ([{(c-b)(c-b)-2bc.(cos A-1)}^1/2]/c+b)^2.cb
Suppose you are given one angle A and the ratio is R so that the other two angles are B and BxR.Then: A + B + BxR = 180.B (1 + R) = 180 - Aso the answer is B = (180 - A) / (1 + R)e.g. you are given A=60 and R=2so B = (180 - 60) / (1 + 2) = 40 and the last angle is 80.
If we have y=a(b)^t as the equation then take b from this equation case !: If b <1 then b=1-r r=1-b this r is the decay factor case 2:If b >1 then b=1+r r=b-1 this is the growth factor
It isnC0*A^n*b^0 + nC1*A^(n-1)*b^1 + ... + nCr*A^(n-r)*b^r + ... + nCn*A^0*b^n where nCr = n!/[r!*(n-r)!]
To calculate resistance in parallel: 1/R = 1/A + 1/B + 1/C + 1/D ... where R is the final result, and A, B, C... are the individual resistances. For two resistances A and B, you can simply calculate (A x B) / (A + B).
T r+1 = (n / r) (a ^n-r) x (b)^r
The inverse of a relation is obtained by swapping the pairs in the relation. If a relation ( R ) consists of pairs ((a, b)), then its inverse ( R^{-1} ) consists of pairs ((b, a)) for all pairs in ( R ). This means that if ( a ) is related to ( b ) in ( R ), then ( b ) will be related to ( a ) in ( R^{-1} ). The inverse relation effectively reverses the direction of the relationship between the elements.
For brevity, (since only one 'move' is possible at any one time), the following sequence should solve the game; where R=Red and B=Blue: R B B R R R B B B B R R R R B B B B R R R B B R
these r maths problems they r quite hard
cube = a 3rectangular prism = a b cirregular prism = b hcylinder = b h = pi r 2 hpyramid = (1/3) b hcone = (1/3) b h = 1/3 pi r 2 hsphere = (4/3) pi r 3ellipsoid = (4/3) pi r1 r2 r3
P=B×RB=P÷RR=P÷B
1 rotten apple in every barrel
Let the sides be a,b,c,(opposite to BC,AC,AB): Let the angle be enclosed at vertex A.Let R be the length of the angle bisector.The formula to find R is:cb= R*R + ([{(c-b)(c-b)-2bc.(cos A-1)}^1/2]/c+b)^2.cb
b***h running after tony