T=Period F=frequency T=1/F Period=1/F
P | T T F F Q | T F T F Q' | F T F T P + Q' | F T F F The layout is the best I could do with this software. Hope it is OK.
31
f=t/t; t=1/f
Proof: P{T>n+m/T>n}=P{T>n+m,T>n}/P{T>n} (Bayes theorem) =P{T>n+m}/P{T>n} =((1-p)^(n+m))/(1-p)^n = (1-p)^(n+m-n) = (1-p)^m (1-p)^m = {T>m} So T>m has the same probability as T>m+n given that T>n, which means it doesn't care (or don't remember) that n phases had passed.
p > q~qTherefore, ~p| p | q | p > q | ~q | ~p || t | t | t | f | f || t | f | t | t | f || f | t | t | f | t || f | f | t | t | t |
p --> q and q --> p are not equivalent p --> q and q --> (not)p are equivalent The truth table shows this. pq p --> q q -->(not)p f f t t f t t t t f f f t t t t
P Q (/P or /Q) T T F T F T F T T F F T
T=Period F=frequency T=1/F Period=1/F
P | T T F F Q | T F T F Q' | F T F T P + Q' | F T F F The layout is the best I could do with this software. Hope it is OK.
it is true when at least one statement is true p q p v q t t t t f t f t t f t f You sure about this?
1 Potato, two potato, three potato, four, (five potato, six potato, seven potato more).
1 penny for a fertile thought 1 pancake for a fussy toddler
31
omfg i have no idea
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 1 words with the pattern T-P----F-. That is, nine letter words with 1st letter T and 3rd letter P and 8th letter F. In alphabetical order, they are: tipstaffs
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 1 words with the pattern -P--T-F. That is, seven letter words with 2nd letter P and 5th letter T and 7th letter F. In alphabetical order, they are: sportif