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The magnitude is the same, the direction vector is not.
There are two possible answers to this; a) It has no direction b) It points in all directions Answer a is really more true, as the notion of a null vector precludes any notion of a direction, but the correct answer is b.
(B^-1)B = 1 B^(-1xB) = 1/(B^B)
Consider any two points on the vector, P = (a, b) and Q = (c, d). And lext x be the angle made by the vector with the positive direction of the x-axis. Then either a = c, so that the vector is vertical and its direction is straight up or a - c is non-zero. In that case, tan(x) = (b - d)/(a - c) or x = tan-1[(b - d)/(a - c)]