1/36 = (1/6)2
2
1 m^(2) + 1 m^(2) = 2m ^(2)
It is -1 over x-squared.
The answer is 1. sin^2 x cos^2/sin^2 x 1/cos^2 cos^2 will be cancelled =1 sin^2 also will be cancelled=1 1/1 = 1
It is 1/2*m*e^2
1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5
One over A squared or A to the negative 2.
2/x + 1/x2 = (2x+1)/x2
x^-2
1 m^(2) + 1 m^(2) = 2m ^(2)
2
(4/100)2 = 16/10,000 or 1/625
Q: I = -1 squared then I to the power of 2 =? I = -1
104
2 squared 1 = 4 so the divisibility rule is that it is divisible by 1, 2 and 4.
Multiply both sides by sin(1-cos) and you lose the denominators and get (sin squared) minus 1+cos times 1-cos. Then multiply out (i.e. expand) 1+cos times 1-cos, which will of course give the difference of two squares: 1 - (cos squared). (because the cross terms cancel out.) (This is diff of 2 squares because 1 is the square of 1.) And so you get (sin squared) - (1 - (cos squared)) = (sin squared) + (cos squared) - 1. Then from basic trig we know that (sin squared) + (cos squared) = 1, so this is 0.