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Q: 1 squared plus 1 squared plus 2 squared plus 3 squared plus 5 squared plus 8 squared equals?

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2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.

1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5

P^2 + p^2 cannot be simplified.

no if 1 plus 1 equals 2 then 2 plus 2 equals 4.

5

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2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.

1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5

y-1=(x-2)^1/2

yes 1 + cot x^2 = csc x^2

X=1/2

No because no 2 numbers can be squared to equal 4. 1 squared is 1 2 squared is 4 so the lowest answer is 5.

b = sqrt32 or 4 root 2

F(x)=[x^2]+1

The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.

Simple equation lad. In your example, you said n=4 and x= n squared + n - 1 + (n-2)squared + (n-3)squared. You simply write n²+n-1+(n-2)²+(n-3)² I hope that is what you mean by what you say. P.S. To get the to the power of sign, hold alt and press 0178 for ², and 0179 for ³

2 squared plus 2 squared equals 16 because 2 squared is 4 times 4 equals 16. Math: 4x4=16 so your answer is 16 :)!

No, (sinx)^2 + (cosx)^2=1 is though