1/[sqrt(3) - 2]
Use the conjugate in a form of 1..... sqrt(3) + 2/sqrt(3) + 2
1/sqrt(3) - 2 * sqrt(3) + 2/sqrt(3) + 2
sqrt(3) + 2/3 - 4
sqrt(3) + 2/- 1
= - sqrt(3) + 2
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1 over 2 times radical 6
8
(a-2(ab)1/2+b)/(a-b)
(1 over radical three) over three - I assume that's how you are describing it - can be simplified like any division problem involving fractions in the numerator and denominator. To solve the problem, you take the fraction in the denominator (in this case 3 over 1) and invert it (making it 1 over 3) and multiply it by the numerator. You would have (1 over radical 3) times (1 over 3) which would give you 1 over (3 times radical 3)
5.6568542
radical(13) over 13.
1 over 2 times radical 6
8
(a-2(ab)1/2+b)/(a-b)
(1 over radical three) over three - I assume that's how you are describing it - can be simplified like any division problem involving fractions in the numerator and denominator. To solve the problem, you take the fraction in the denominator (in this case 3 over 1) and invert it (making it 1 over 3) and multiply it by the numerator. You would have (1 over radical 3) times (1 over 3) which would give you 1 over (3 times radical 3)
32 over 32. Or 32 over 1.
5.6568542
5/32 + 1/2 = 5/32 + 16/32 = 21/32
3.125% 32/1
1/2 minus 5/32 is 11/32
8 divided by 1/4 is 32.
1/32 = 0.03125