the square root of 9 is 3 so 1 +3 = 4
It is 16 +/- 12*sqrt(3)*i where i is the imaginary square root of -1
10 square root of 3.
Square root of 3=1 so 1+4=5
2.309401, rounded to the 6th decimal place.
the square root of 9 is 3 so 1 +3 = 4
root 3 - 1 all over 2
It is 16 +/- 12*sqrt(3)*i where i is the imaginary square root of -1
10 square root of 3.
x2+3i=0 so x2=-3i x=square root of (-3i)=square root (-3)square root (i) =i(square root(3)([1/(square root (2)](1+i) and i(square root(3)([-1/(square root (2)](1+i) You can multiply through by i if you want, but I left it since it shows you where the answer came from. Note: The square root of i is 1/square root 2(1+i) and -1/square root of 2 (1+i) to see this, try and square them!
Square root of 3=1 so 1+4=5
2.309401, rounded to the 6th decimal place.
It is sqrt(3)*[1 + sqrt(2)]/3 or [1 + sqrt(2)]/sqrt(3)
10 square root 3.
10.3...
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The exact square root of 9999999999999999999999 is 33 times the square root of 9182736455463728191.