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You can treat the BC years like negative numbers except that you need to compensate for the fact that there is no year 0 (the year before A.D. 1 is 1 B.C.). If you add to a B.C. year and you get a number greater than -1, add 1 more to compensate for the lack of year 0. For example, to calculate what year was five years after 2 B.C., add five to negative two: -2 + 5 = 3 Since 3 is greater than -1, add 1 more: 3 + 1 = 4 So A.D. 4 is five years after 2 B.C. Likewise, when you're subtracting from a positive (AD) year and you get a number less than 1, subtract 1 more for the lack of year 0. For example, to find the last leap year BC, subtract 4 years from the first leap year AD: 4 - 4 = 0 Since 0 is less than 1, 0 - 1 = -1 So the last leap year BC was 1 BC.
The year 867 BC, as with any year between 900 BC and 801 BC, falls in the ninth century BC.
x = 0.125 ( BC - 7 )
I assume that points BC is a straight line and that D is the point where the line DE intersects BC. If this is so, and CDE is 55 degress, then BDE is 125 degrees.
10 BC was in the first century BC.