Here today, gone tomorrow. H + ear (ere) : calendar = today : g + on = gone : 2 + morrow = tomorrow.
2d+2h+2t+g+f+2r+w+x
=b+2h+r+x+z+q+a+p+l+f+g+d
2 + g + 5 = g + 7
If I'm reading the question correctly: y = 1 / (4x + 2) The slope is the derivative. Using the quotient rule (see related link): d/dx of g(x)/h(x) = ( g'(x)h(x) - g(x)h'(x) ) / (h(x))2 So, g(x) = 1, and h(x) = 4x + 2, and g'(x) = 0, h'(x) = 4. So dy/dx = -4/(4x + 2)2.
Here today, gone tomorrow. H + ear (ere) : calendar = today : g + on = gone : 2 + morrow = tomorrow.
7g-10h
h(x)=3x-4
The answer is 0
2d+2h+2t+g+f+2r+w+x
The equilibrium constant, K_eq, for the reaction 2HCl (g) → H₂ (g) + Cl₂(g) is equal to [H₂][Cl₂]/[HCl]².
=b+2h+r+x+z+q+a+p+l+f+g+d
2 + g + 5 = g + 7
36g2h2 = 2*2*3*3*g*g*h*h provided g and h are prime.
If I'm reading the question correctly: y = 1 / (4x + 2) The slope is the derivative. Using the quotient rule (see related link): d/dx of g(x)/h(x) = ( g'(x)h(x) - g(x)h'(x) ) / (h(x))2 So, g(x) = 1, and h(x) = 4x + 2, and g'(x) = 0, h'(x) = 4. So dy/dx = -4/(4x + 2)2.
g h plus r d g is the sister of (h plus (r is a sister of d)) g is the sister of h is the father of r is the sister of d so g is d's aunt.
13g