G plus 5 * 16 = G + 80
What is g + (-5) = 27
gf(5) = g(f(5)) = g(5+1) since f(x) = x+1 and then g(6) = 3*6 - 2 = 18 - 2 = 16
13g
It is g > -1.
(g + 5)(g + 2)
If G + 5 = g - 2 then G = g + 3 and g = G - 3
f(x) = 3x - 1 so f(-2) = 3*(-2) - 1 = -7 g(x) = - x so g(5) = - 5 Then f(-2) + g(5) = -7 - 5 = -12
G plus 5 * 16 = G + 80
What is g + (-5) = 27
gf(5) = g(f(5)) = g(5+1) since f(x) = x+1 and then g(6) = 3*6 - 2 = 18 - 2 = 16
-0.8 or -4/5 is the solution to the equation -2g + 4 + 7g.
13g
It is g > -1.
If "g" has a value then it would just be 5+(the value) Otherwise it would be 5+g G is a variable and therefor could be anything. You can not solve the equation further. The answer is simply 5+G. If you have a previous declaration that states that G=2, then 5+G would equal 7. In computer programming, equations like this are useful for repetitious calculations. For example, if G is the variable for a score in a game, we would start with G=0 and every time you get a point, the computer would calculate G=G+1. G, currently 0, plus 1, equals 1. If you get another point then G, currently 1, plus 1, equals 2. This can be repeated as needed without changing the equation.
g(x) = x + 3 Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)
To find f(g(-2)), we need to substitute -2 into g(x) first. Thus, g(-2) = 22 - 1 = 21. Now, we can substitute g(-2) = 21 into f(x). So, f(g(-2)) = f(21) = 4(21) + 5 = 89. Therefore, f(g(-2)) is equal to 89.