2 + g + 5 = g + 7
G plus 5 * 16 = G + 80
What is g + (-5) = 27
To find ( f(x) + g(x) ), we first write the functions: ( f(x) = 3x^2 + 4x + 5 ) and ( g(x) = 2x^2 + 3x + 1 ). Adding them together, we combine like terms: [ f(x) + g(x) = (3x^2 + 2x^2) + (4x + 3x) + (5 + 1) = 5x^2 + 7x + 6. ] Thus, ( f(x) + g(x) = 5x^2 + 7x + 6 ).
gf(5) = g(f(5)) = g(5+1) since f(x) = x+1 and then g(6) = 3*6 - 2 = 18 - 2 = 16
13g
(g + 5)(g + 2)
If G + 5 = g - 2 then G = g + 3 and g = G - 3
f(x) = 3x - 1 so f(-2) = 3*(-2) - 1 = -7 g(x) = - x so g(5) = - 5 Then f(-2) + g(5) = -7 - 5 = -12
G plus 5 * 16 = G + 80
What is g + (-5) = 27
To find ( f(x) + g(x) ), we first write the functions: ( f(x) = 3x^2 + 4x + 5 ) and ( g(x) = 2x^2 + 3x + 1 ). Adding them together, we combine like terms: [ f(x) + g(x) = (3x^2 + 2x^2) + (4x + 3x) + (5 + 1) = 5x^2 + 7x + 6. ] Thus, ( f(x) + g(x) = 5x^2 + 7x + 6 ).
gf(5) = g(f(5)) = g(5+1) since f(x) = x+1 and then g(6) = 3*6 - 2 = 18 - 2 = 16
-0.8 or -4/5 is the solution to the equation -2g + 4 + 7g.
13g
If "g" has a value then it would just be 5+(the value) Otherwise it would be 5+g G is a variable and therefor could be anything. You can not solve the equation further. The answer is simply 5+G. If you have a previous declaration that states that G=2, then 5+G would equal 7. In computer programming, equations like this are useful for repetitious calculations. For example, if G is the variable for a score in a game, we would start with G=0 and every time you get a point, the computer would calculate G=G+1. G, currently 0, plus 1, equals 1. If you get another point then G, currently 1, plus 1, equals 2. This can be repeated as needed without changing the equation.
It is g > -1.
g(x) = x + 3 Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)