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(2 x 100000000) + (2 x 10000000) + (7 x 1000000) + (9 x 100000) + (0 x 10000) + (0 x 1000) + (0 x 100) + (0 x 10) + (0 x 1)
NINE (9) 1000,2000,3000,4000,5000,6000,7000,8000,9000
99.9999 = (9 x 10) + (9 x 1) + (9/10) + (9/100) + (9/1000) + (9/10000).
(9 x 1) + (0/10) + (4/100) + (0/1000) + (2/10000)
To determine how many times the digit 9 is written when writing numbers from 1 to 10000, we can consider the pattern of its occurrence in each place value. In the units place, the digit 9 appears 1000 times (from 9 to 9999). In the tens place, the digit 9 appears 1000 times (from 90 to 99, 190 to 199, and so on). In the hundreds place, the digit 9 appears 1000 times (from 900 to 999, 1900 to 1999, and so on). Therefore, the digit 9 is written 3000 times in total when writing numbers from 1 to 10000.