10000
Yuo can make only one combination of 30 digits using 30 digits.
9
If you use each number once, there are six combinations.
12, including a combination containing 0 digits.
In other words, how many 4 digit combination locks are there using the digits 0-9 on each wheel. There are 10×10×10×10 = 10⁴ = 10,000 such combinations.
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
All the possible digits (10 of them; 0-9) are multiplied by themselves by the number of digits that can be shown in the lock. (3) This is 103, or 1,000. This certainly shows why guessing is not a good way to break into a numerical lock, especially since three is a rather low number of digits for one!
6,720 combinations.
5040, assuming none of the digits are the same. (Assuming they're not, there's 5040 unique combinations you can make out of 7 digits).
If a lock has four dials and each dial can display the digits from 0 to 9 without repeating any digits, we can calculate the total combinations as follows: For the first dial, there are 10 options (0-9). For the second dial, there are 9 remaining options (since one digit has already been used), for the third dial, there are 8 options left, and for the fourth dial, there are 7 options. Therefore, the total number of combinations is (10 \times 9 \times 8 \times 7 = 5040) combinations.
6 for 3-digits, 6 for 2-digits, 3 for 1-digits, and 15 for all of the combinations
10,000.
10000
Since a number can have infinitely many digits, there are infinitely many possible combinations.
45
There are 167960 9 digits combinations between numbers 1 and 20.
10x9x9x9