10000
Yuo can make only one combination of 30 digits using 30 digits.
9
If you use each number once, there are six combinations.
12, including a combination containing 0 digits.
In other words, how many 4 digit combination locks are there using the digits 0-9 on each wheel. There are 10×10×10×10 = 10⁴ = 10,000 such combinations.
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
All the possible digits (10 of them; 0-9) are multiplied by themselves by the number of digits that can be shown in the lock. (3) This is 103, or 1,000. This certainly shows why guessing is not a good way to break into a numerical lock, especially since three is a rather low number of digits for one!
6,720 combinations.
5040, assuming none of the digits are the same. (Assuming they're not, there's 5040 unique combinations you can make out of 7 digits).
If a lock has four dials and each dial can display the digits from 0 to 9 without repeating any digits, we can calculate the total combinations as follows: For the first dial, there are 10 options (0-9). For the second dial, there are 9 remaining options (since one digit has already been used), for the third dial, there are 8 options left, and for the fourth dial, there are 7 options. Therefore, the total number of combinations is (10 \times 9 \times 8 \times 7 = 5040) combinations.
10,000.
6 for 3-digits, 6 for 2-digits, 3 for 1-digits, and 15 for all of the combinations
10000
Since a number can have infinitely many digits, there are infinitely many possible combinations.
45
The number of combinations you can make with the digits 1234567890 depends on how many digits you want to use and whether repetition is allowed. If you use all 10 digits without repetition, there are 10! (10 factorial) combinations, which equals 3,628,800. If you are choosing a specific number of digits (for example, 3), the number of combinations would be calculated using permutations or combinations based on the rules you set.
There are 167960 9 digits combinations between numbers 1 and 20.