3X + 6 + X = 86 add the like terms, X's, together 4X + 6 = 86 subtract 6 from each side 4X = 80 divide both sides by 4 X = 20 check 3(20) +6 + (20) = 86 86 = 86 checks
2x+6 = x+3 the x cancels out the other x x+6=3 subtract 6 from both sides x+6 -6 = 3 -6 x= - 3
If: y = x² + 9 and y = 6x + 2 then x² + 9 = 6x + 2 → x² - 6x + 7 = 0 → x = (6 ± √(6² - 4×1))/2 = (6 ± √8)/2 = (6 ± 2√2)/2 = 3 ± √2 Substituting in the second to find the corresponding y: → x = 3 - √2 → y = 6(3 - √2) + 2 = 20 - 6√2 or x = 3 + √2 → y = 6(3 + √2) + 2 = 20 + 6√2 The solution is the two points: (3 - √2, 20 - 6√2) and (3 + √2, 20 + 6√2)
The answer to 3 plus X plus -7 times 6 equals-38. This is considered to be a math problem.
5X-3 - X-1 + X + 6 The answerdepends on value of X
3X + 6 + X = 86 add the like terms, X's, together 4X + 6 = 86 subtract 6 from each side 4X = 80 divide both sides by 4 X = 20 check 3(20) +6 + (20) = 86 86 = 86 checks
x+3 = 20 x = 20-3 x = 17
When x = 3, 3 plus x = 6.
To get the answer to this question you would do this: 6-20=14 14+6=20 X=14
balance the equation 3x-x=20-6 3x-x=2x 20-6=14 2x=14 x=7
2x+6 = x+3 the x cancels out the other x x+6=3 subtract 6 from both sides x+6 -6 = 3 -6 x= - 3
2x/3=x/2+20 (2x/3=x/2+20)6 4x=3x+120 4x-3x=120 x=120
9
If: y = x² + 9 and y = 6x + 2 then x² + 9 = 6x + 2 → x² - 6x + 7 = 0 → x = (6 ± √(6² - 4×1))/2 = (6 ± √8)/2 = (6 ± 2√2)/2 = 3 ± √2 Substituting in the second to find the corresponding y: → x = 3 - √2 → y = 6(3 - √2) + 2 = 20 - 6√2 or x = 3 + √2 → y = 6(3 + √2) + 2 = 20 + 6√2 The solution is the two points: (3 - √2, 20 - 6√2) and (3 + √2, 20 + 6√2)
The answer to 3 plus X plus -7 times 6 equals-38. This is considered to be a math problem.
-6 x -3 + (-6) = +18 -6 = +12
-2x+14=20 -2x=20-14 -2x=6 -2x/-2=6/-2 x=-3