In mathematics, the multiplication problem 20 times 36 is 720.
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3X + 6 + X = 86 add the like terms, X's, together 4X + 6 = 86 subtract 6 from each side 4X = 80 divide both sides by 4 X = 20 check 3(20) +6 + (20) = 86 86 = 86 checks
2x+6 = x+3 the x cancels out the other x x+6=3 subtract 6 from both sides x+6 -6 = 3 -6 x= - 3
If: y = x² + 9 and y = 6x + 2 then x² + 9 = 6x + 2 → x² - 6x + 7 = 0 → x = (6 ± √(6² - 4×1))/2 = (6 ± √8)/2 = (6 ± 2√2)/2 = 3 ± √2 Substituting in the second to find the corresponding y: → x = 3 - √2 → y = 6(3 - √2) + 2 = 20 - 6√2 or x = 3 + √2 → y = 6(3 + √2) + 2 = 20 + 6√2 The solution is the two points: (3 - √2, 20 - 6√2) and (3 + √2, 20 + 6√2)
The answer to 3 plus X plus -7 times 6 equals-38. This is considered to be a math problem.
5X-3 - X-1 + X + 6 The answerdepends on value of X