20 x 3 and 20 + 2
4x =20x=20/4x=5
5x+3 = -17 5x = -17-3 5x = -20 x = -4
3x + 8 = 20 3x = 20 - 8 3x = 12 3x = 12/3 x = 4
3x^2=-20 so x^2=-20/3 this has no real roots but the plus of minus i(square root of 20/3) is a solution if we allow complex numbers.
x=8.5
x = 20
20
x=3
1 + x + 2x = 20 So 1 + 3x = 20 so that 3x = 19 then x = 19/3 or 61/3
(20 * x) + 3 = 5 20 * x = 2 x = 1/10
-14
-2x+14=20 x=-3
20 x 3 and 20 + 2
x=6=x=5+x=13+x=20 x cannot = x+5. This question has no answer.
4x =20x=20/4x=5
You don't know that?! If x=3, then 6x is 6x3. So 18 plus 2 is.....20!!