Q: What is 20cm enlarged by 20 percent?

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The answer is 20cm

Convert them all into the same unit, for this case let's say cm. 20cm = 20cm 20 inches = 50.8cm 200mm = 20cm When you type 02m, do you mean 2m or 0.2m? 0.2m = 20cm 2m = 200cm If 0.2m, then 20 inches is the longest length. If 2m then that is the longest length.

12 enlarged by 130% = 12*1.3 = 15.6

Use 1/s + 1/s' = 1/f s = 20cm f = +10cm (positive since the mirror is concave) 1/s'=1/f - 1/s 1/s'=1/10 - 1/20 = 1/20 So, s'=20cm. The distance from the image to the mirror is 20cm, which is not surprising, since the object placed at 1/2 of the focal length and therefore exactly at the radius of curvature point. The image is real and inverted.

To find the percentage, you can use the formula: (20cm / 800mm) * 100. Simplifying this, you get (2.5 / 100) * 100 = 2.5%. Therefore, 20cm is 2.5% of 800mm.

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1 equal 20'/3 = 6.66...' or 6'8"

The answer is 20cm

Convert them all into the same unit, for this case let's say cm. 20cm = 20cm 20 inches = 50.8cm 200mm = 20cm When you type 02m, do you mean 2m or 0.2m? 0.2m = 20cm 2m = 200cm If 0.2m, then 20 inches is the longest length. If 2m then that is the longest length.

5 per cent of 20 is 1. So if the student makes a mistake of exactly 5 per cent then his measurements are 20 +/- 1 cm. That is, 19 or 21 cm.

12 enlarged by 130% = 12*1.3 = 15.6

It is: 10/200 = 1/20

Use 1/s + 1/s' = 1/f s = 20cm f = +10cm (positive since the mirror is concave) 1/s'=1/f - 1/s 1/s'=1/10 - 1/20 = 1/20 So, s'=20cm. The distance from the image to the mirror is 20cm, which is not surprising, since the object placed at 1/2 of the focal length and therefore exactly at the radius of curvature point. The image is real and inverted.

To find the percentage, you can use the formula: (20cm / 800mm) * 100. Simplifying this, you get (2.5 / 100) * 100 = 2.5%. Therefore, 20cm is 2.5% of 800mm.

20 -:$:7

11cm by 20cm = 220cm2

It is: 20*7 = 140 square cm