30 x 80 = 2400 80 x 30 = 2400
156 x 2 = 312
2400 x 6.25% = 150
X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers
39 x 4 =156
30 x 80 = 2400 80 x 30 = 2400
5 x 2400 = 12000 5% of 2400 = 120
156 x 2 = 312
2400 x 4 = 9600
2400 x 6.25% = 150
X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers
39 x 4 =156
1 x 156, 2 x 78, 3 x 52, 4 x 39, 6 x 26, 12 x 13 = 156
1 x 156, 2 x 78, 3 x 52, 4 x 39, 6 x 26, 12 x 13 = 156
2 x 2 x 2 x 2 x 2 x 3 x 5 x 5 = 2400
12 x 13 = 156 How to find the answer: If x is the first integer, then x+1 is the next consecutive integer. so x(x+1) = 156 or x^2 + x -156 =0 solve the quadratic equation for x.
200. 12 x 200 = 2400